Question

(sin A - 2 sin3A)/(2 cos3A - cos A) = tan A​

Answer 1

Answer:

sinA(1-2sin^2A)/cosA(2cos^2A-1)

then substitute the value of cosA as 1-sin^2A

sinA(1-2sin2A)/cosA(2(1-sin2A)-1)

sinA(1-2sin2A)/cosA (1-2sin2A)

there fore sinA/cosA is tanA

so lhs= rhs

hence proved. hope this helps

Answer 2

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