Question

sin A =3/2 find cosA + tan A​

Answer 1

Answer:

It doesn't exist

Step-by-step explanation:

sin A = opposite side/ hypotenuse

Sin A = 3/2

Beacause the hypotenuse is the largest side in right angle triangle

so, it doesn't exist

Answer 2

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

$\sin(a) = \frac{3}{2}$

u have typed wrong I think coz( 3/2)>1

and sin(a) can't be >1

so I take it=2/3

$\sin(a) = \frac{2}{ 3} \\ = > \sqrt{1 - \cos {}^{2} (a) } = \frac{2}{3} \\ = > \cos {}^{2} (a) = 1 + \frac{4}{9} \\ = > \cos(a) = \frac{ \sqrt{13} }{3} \\ therefore$

$\tan(a) = \frac{ \sin(a) }{ \cos(a) } = \frac{ \frac{2}{3} }{ \frac{ \sqrt{13} }{3} } = \frac{2}{ \sqrt{13} }$

therefore..

$\cos(a) + \tan(a) = \frac{ \sqrt{13} }{3} + \frac{2}{ \sqrt{13} } \\ = \frac{13 + 6}{3 \sqrt{13} } \\ = \frac{19}{3 \sqrt{13} }$