Question

sin A=√3/2,sin B=1, then find sin (B-A)?​

Answer 1

Given :

• sin A = √3/2

• sin B = 1

To Find :

• Value of sin ( B - A )

Solution :

$\implies \sf \sin A= \frac{ \sqrt{3} }{2} \\ \\\implies \sf \sin A = \sin 60\degree \\ \\\implies \sf A = 60 \degree$

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$\implies \sf\sin B= 1 \\ \\ \implies \sf \sin B= \sin90 \\ \\\implies \sf B = 90\degree$

Now

$\implies \sf\sin(b - a) \\ \\ \implies \sf \sin(90 - 60) \\ \\ \implies \sf \sin30\degree \\ \\ \implies \sf \frac{1}{2}$

$\large\underline{ \green{\sf \therefore \: \sin(b - a) = \dfrac{1}{2}}}$

Answer 2

sin A = √3/2

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sin A = 60°

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sin A = sin 60°

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A = 60°

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sin B = 1

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sin B = 90°

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sin B = sin 90°

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B = 90°

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therefore,

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sin ( B - A )

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sin ( 90° - 60° )

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sin 30°

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sin 30° = 1/2