Question

sin(A-B)=1÷2and cos(A+B)=1÷2then find A and B

Answer 1

$\sin(A-B) = \frac{1}{2} \\ so \: \: A-B = 30° - - - (1) \\ \cos(A + B) = \frac{1}{2} \\ so \: \: A + B = 60° - - - (2) \\ (1) + (2) \: \: gives \\ 2A = 90° \\ A = 45° \\ from \: \: (1) \\ B = 45 - 30 = 15°$