Question

sin (A+B) = 1 , cos (A - B) = √3/2 then find LA
LB​

Answer 1

Answer:

sinx=1

so x=90°

cosy=√3/2

so y =30°

here x is a+b and y is a-b

a+b=90 and a-b=30

so a=60° and b=30°

Thanks

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Answer 2

$sin(a + b) = 1 \\ we \: know \: that \: \sin(90) = 1 \\ therefore \: (a + b )= 90 \: \: \: \: \: ...(i) \\ cos(a - b) = \frac{ \sqrt{3} }{2} \\ we \: know \: that \: cos(30) = \frac{ \sqrt{3} }{2} \\ therefore \: (a - b) = 30 \: \: \: \: \: ...(ii) \\ adding \: (i) \: and \: (ii)... \\ 2a = 120 \\ = > a = 60 \\ b = 90 - 60 = 30 \\ therefore \: a = 60 \: and \: b = 30$