Question

Sin A =b/a .Find Cos A.​

Answer 1

Answer:

$\sqrt{a^{2} + b^{2} }$ / a

Step-by-step explanation:

SinA=Opposite/Hypotenuse

Therefore b is opposite where as a is the hypotenuse.

using pythagoras theorem, we get

$a^{2}$ = $b^{2}$ + Adjacent

$a^{2}$ - $b^{2}$ = Adjacent

$a^{2}$ - $b^{2}$ = $\sqrt{a^{2} + b^{2} }$

thus CosA=Adjacent/Hypotenuse

= $\sqrt{a^{2} + b^{2} }$ / a