Question

sin(A+B)cos(A-B)-cos(A+B)sin(A-B)=sin2B.

Answer 1

Hi friend!!

We know that

sinxcosy-cosxsiny=sin(x-y)

Given,

sin(A+B)cos(A-B)-cos(A+B)sin(A-B)

=sin (A+B-(A-B))

=sin (A+B-A+B)

=sin2B

Hence proved.

I hope this will help you ;)