Question

sin(A+B). cos(A-B) +sin(A-B). cos(A+B) =​

Answer 1

we have

sin(A+B). cos(A-B) +sin(A-B). cos(A+B)

By using sin(A).cos(B) + sin(B).cos(A) = sin (A+B) we get

sin[(A+B) + (A-B)] = sin (2A)

By using sin(2x) = 2sin(x) . cos(x) we get

2 sin(A) . cos (A)

Answer 2

Step-by-step explanation:

The answer is

sin2A

Mark me as a BRAINLIST my friend..