Math, asked by charitha6002, 1 month ago

sin(a+b)cos(a-b)+sin(a-b)cos(a+b)=

Answers

Answered by nishtirumalaraju

0

Answer:

sin2a

Step-by-step explanation:

The given question is in the form ...

sin(A+B)= sinA.cosB+cosA.sinB

where A=a+b. B=a-b

sin(a+b)cos(a-b)+sin(a-b)cos(a+b)=sin(a+b+a-b)

=sin(2a)

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