sin( A + B) + sin(A – B) =
Answers
Answered by
0
Answer:
sin(A+B).sin(A−B)
=[sin(A)cos(B)+cos(A)sin(B)][sin(A)cos(B)−cos(A)sin(B)]
=sin
2
Acos
2
A−cos
2
Asin
2
A
=sin
2
A[1−sin
2
B]−[1−sin
2
A]sin
2
B
=sin
2
A−sin
2
Asin
2
B−sin
2
B+sin
2
Asin
2
B
=sin
2
A−sin
2
B
Answered by
1
Answer:
Sin2A
Step-by-step explanation:
SinA+SinB+SinA-SinB
therefore Sin2A
please mark as brainliest answer
Similar questions