sin(a+b)+sin (c+d) =0
Answers
Answered by
2
what i need to find in this ques
mona244:
u have to prove it
ohh
wait
sin (a+b)+sin (c+d)=2sin(a+b+c+d/2)cos(a+b-c-d/2)
=0
then find the value of a+b;c+d
u get the answer
Answered by
4
A + B + C + D = 360
(A+B) = 360 - (C+D)
sin (A+B) = sin {360 - (C+D)} = -sin(C+D)
So, sin(A+B) + sin(C+D) = -sin(C+D) + sin(C+D) = 0
Mark as brainliest
Similar questions