Math, asked by MouliRock, 7 months ago

sin(A+B)=sinA cosB+cosA sinB,tan(A+B)=tan A+tan B÷1-tan A tan B,tan(A-B)=tan A-tan B÷1+tan A tan B then value of sin 75° is

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Answered by durgeshk3698

36

Answer:

sin(A+B)=sinA cosB+cosA sinB,tan(A+B)=tan A+tan B÷1-tan A tan B,tan(A-B)=tan A-tan B÷1+tan A tan B then value of sin 75° is

Answered by guptapreeti051181

5

Answer:

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