sin A - cos A + 1 / sin A + cos A - 1
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Answer:
sinA/CosA-cosA/CosA+1/Cosa
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SinA/CosA+CosA/CosA-1/CosA
= TAN A + SECA- 1
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TANA-SECA+ 1
(tanA+SecA)-(sec2A- Tan2A)
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tanA-SecA + 1
(TanA+SecA)-[(SecA+ TanA)SecA- TanA)
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TanA - SecA + 1
(SecA+ TanA) [1-SecA+ TanA)
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(1-SecA+ TanA)
=SecA + TAN A
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