Math, asked by yasorhere, 3 months ago

Sin a/cos a +cos a/sina=cosec a seca

Answers

Answered by arunpatodi18

0

Answer:

this is the answer pls mark brainliest

Attachments:

Answered by Anonymous

0

Step-by-step explanation:

LHS=

cosA+sinA

cosAcosecA−sinAsecA

=

sinAcosA(cosA+sinA)

cos

2

A−sin

2

A

=

sinAcosA(cosA+sinA)

(cosA−sinA)(cosA+sinA)

=

sinAcosA

cosA−sinA

=

sinA

1

−

cosA

1

=cosecA−secA

=RHS

Hence proved

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