(sin A + cos A) (sec A + cosec A)=
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Answered by
3
heya,
I think ,
(sinA+ cosA)(secA+ cosecA)
= sinA+cosA×1/ cosA+1/sinA
=sin^2A+cos^2A+2sinA*cosA/sinA*cosA
=1+2sinA*cosA/sinA*cosA
cosecA*secA+2 ans
hope it help you .
@rajukumar
I think ,
(sinA+ cosA)(secA+ cosecA)
= sinA+cosA×1/ cosA+1/sinA
=sin^2A+cos^2A+2sinA*cosA/sinA*cosA
=1+2sinA*cosA/sinA*cosA
cosecA*secA+2 ans
hope it help you .
@rajukumar
gudu9058gmailcom:
you are wrong ,correct answer is tanA +cotA +2
Answered by
0
=sinA +cosA ×1/cosA +1/sinA
= (sinA+cosA)^2
=sin^2A+cos^2A+2sinA×cosA
=1+2sinA×cosA
= (sinA+cosA)^2
=sin^2A+cos^2A+2sinA×cosA
=1+2sinA×cosA
you are wrong , correct answer is 2(cosec2A +1)
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