Question

Sin A + cos b is equal to 1 b is equal to 60 degree and a is an acute angle then find the value of A​

Answer 1

SOLUTION

GIVEN

• sin A + cos B = 1

• B = 60°

• A is an accute angle

TO DETERMINE

The value of A

EVALUATION

Here it is given that

sin A + cos B = 1

Now B = 60°

Therefore we get

$\sf{ \sin A + \cos {60}^{ \circ} = 1}$

$\displaystyle \sf{ \implies \: \sin A + \frac{1}{2} = 1}$

$\displaystyle \sf{ \implies \: \sin A = 1 - \frac{1}{2} }$

$\displaystyle \sf{ \implies \: \sin A = \frac{1}{2} }$

$\displaystyle \sf{ \implies \: A = {30}^{ \circ} }$

FINAL ANSWER

A = 30°

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Answer 2

Answer:

if sin a + cos b= 1

b= 60.

sin a+ cos 60= 1

cos 60= 1/2

therefore , sina + 1/2= 1

sina= 1/2-1

sina =1/2

sin 30 = 1/2

therefore a = 30