Question

(sin A + cosec A)2 + (cos A + sec A)2
= 7+tan A + cotA (AS, AS)​

Answer 1

Answer:

= sin2A + cosec2A + cos2 +sec2A

= sin2A + cos2A + cosec2A +sec2A +2 sinA*cosecA + 2cosA* secA

= 1 + tan2A + 1 + cot2A + 1 + 2 + 2

{sin2A + cos2A = 1}

{cot2A + 1 = cosec2A}

{ tan2A + 1= sec2A}

{ sec2A= 1/cos2A}

{sin2A= 1/cosec2A}

= 7+ tan2A + cot2A

*RHS = LHS*

hence proved

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