sin a = ½ find 2 sec a ÷ 1+ tan² A
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Answered by
4
sinA = 1/2
sinA = sin30°
Therefore ,
A = 30°
Now ,
2secA / ( 1 + tan² A )
= 2secA / sec²A ( since 1+ tan² A = sec² A )
= 2 / secA
= 2 cos A
= 2 cos30°
= 2 × √3 /2
= √3
sinA = sin30°
Therefore ,
A = 30°
Now ,
2secA / ( 1 + tan² A )
= 2secA / sec²A ( since 1+ tan² A = sec² A )
= 2 / secA
= 2 cos A
= 2 cos30°
= 2 × √3 /2
= √3
Answered by
1
hope it works..............
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