Question

sin a = ½ find 2 sec a ÷ 1+ tan² A

Answer 1

sinA = 1/2 

sinA = sin30°

Therefore ,

A = 30°

Now ,

2secA / ( 1 + tan² A )

= 2secA / sec²A ( since 1+ tan² A = sec² A )

= 2 / secA

= 2 cos A 

= 2 cos30°

= 2 × √3 /2

= √3 

Answer 2

hope it works..............