Sin A minus 2 Sin cube A upon 2 cos cube A minus Cos A is equal to 10
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varunwadikar:
thanks man
Answered by
8
Sin A - 2 Sin^3 A/ 2 cos ^3 A - cos A = tan
L.H.S. = Sin A ( 1 - 2 sin ^2 A)/ cos A ( 2cos^A-1)
= tan A ( sin^2A + cos ^2 A -2 sin^2A) / ( 2 cos^2A - sin^2A - cos ^2A)
= tan A
Hope it helps.....
L.H.S. = Sin A ( 1 - 2 sin ^2 A)/ cos A ( 2cos^A-1)
= tan A ( sin^2A + cos ^2 A -2 sin^2A) / ( 2 cos^2A - sin^2A - cos ^2A)
= tan A
Hope it helps.....
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