Sin A +sin^2 A =1 ,then cos^2 A + cos^4 =??
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sinA + sin^2A=1. ( sin^2A+cos^2A=1)
sinA + ( 1 -cos^2A) = 1. ( sin^2A = 1 - cos^2A)
sinA+cos^2A = 1 -1
sinA=cos^2A
2nd
= cos^2A + cos^4A
= sinA + cos^4A
= sin A + (cos^2)^2. ( cos ^2A =sinA)
=sin A + (sinA)^2
= sinA + sinA^2
= 1
its help you ✌
sinA + sin^2A=1. ( sin^2A+cos^2A=1)
sinA + ( 1 -cos^2A) = 1. ( sin^2A = 1 - cos^2A)
sinA+cos^2A = 1 -1
sinA=cos^2A
2nd
= cos^2A + cos^4A
= sinA + cos^4A
= sin A + (cos^2)^2. ( cos ^2A =sinA)
=sin A + (sinA)^2
= sinA + sinA^2
= 1
its help you ✌
Mahavirsinhzala:
Thanks for your help
its my pleasure✌
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