Question

sin a+sin(60-a)-sin(60+a)​

Answer 1

Step-by-step explanation:

As we know that sin(A+B)sin(A−B)=sin² A−sin² B

LHS=sinAsin(60−A)sin(60+A)=sinA(sin²60−sin² A) $=sinA ( \frac{3}{4} −sin² A)$

$= {3sinA−4sin³A}{4}= \frac{1}{4} \: sin3A=RHS$

Answer 2

$\huge \rm {\underline{Añswer࿐}}$

$\large\bold{=>\frac{1}{4}sin^{3} }$

You Añswer is in the above attachment ⬆️....

@ ᴹⁱˢˢ᭄✿Priyanka࿐