sin A÷sin(90°-A) + cos A ÷ cos(90°-A)= sec A cosec A
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jai96:
thnkuu
wlck
wlcm
Answered by
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sin(90-A)=cos
cos(90-A)=sinA
sin A÷cosA+cosA÷sinA
sinA/cosA +cosA/sin A
LCM=cosA.sinA
sin^2A+cos^2A/sinA.cosA
1/sinA.cosA
secA.cosecA
RHS
hence proved
cos(90-A)=sinA
sin A÷cosA+cosA÷sinA
sinA/cosA +cosA/sin A
LCM=cosA.sinA
sin^2A+cos^2A/sinA.cosA
1/sinA.cosA
secA.cosecA
RHS
hence proved
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