Question

Sin A + sin b is equal to 2 then find the value of sin a + b

Answer 1

Hey !!! ^_^

Here is your answer

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SinA + Sin B = 2

It is only possible when ,

SinA = 1

SinB = 1

A = 1 = 90° and B = 1= 90°


Sin(A + B)

Sin(90° + 90°)

Sin180°

0

The value of SinA + B = 0

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Answer 2

here is your answer OK

We all know that sin is cyclic function from R->[0,1].

So, possible solutions for

sinA +sinB =2

This can only be possible when both sin functions are in maximum.

Hence,

SinA = 1

and A= n (π/2). Where n is odd

And similarly,

B= n (π/2). Where n is odd

Therefore

A+B = (m+n)(π/2) where m,n are odd

A+B = k(π/2) and k is even (as the sum of two odd numbers is even.)

As Sin(A+B)= 0, For all even multiples of π/2

Hence,

Sin(A+B)=0

hope it help you

thanks for ask this question ☺☺