sin A tanA / 1-cosA =1+secA
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Answered by
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Step-by-step explanation:
sin A . tan A/1 - cos A = 1 + sec A
or, sin A. tan A / 1 -cos A = 1 + cos A/ cos A
or, Sin A.cos A. tan A = 1 - cos^ A
or, sin A cos A sinA/ cos A = 1 - cos^ A
or, sin^A = 1 - cos^A
{we know, Sin^A = 1 - cos^A}
L.H.S = R.H.S
[Proved]
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