Political Science, asked by rachitsainionline, 10 months ago

Sin(ax + b) Derive it fast by chain rule and also Derive sec(tan)

Answers

Answered by Rishail6845
2

(1)Let y = (ax + b)

First, we will find Derivative of Sin.

Cos(ax+b).\frac{d}{dx}(ax+b)      .....{sinx = cosx&cosx=-sinx}

cos(ax+b).a

(2)Mate, there is a correction in your ques it's tan√x not tan x.

Now,

Let y = (tan√x)

First, we will find Derivative of sec,

sec(tan \sqrt{x} )tan(tan\sqrt{x} ).\frac{d}{dx}(tan\sqrt{x} )

sec(tan \sqrt{x} )tan(tan\sqrt{x} )*sec^{2} \sqrt{x} \frac{1}{2\sqrt{x} }

Answered by Anonymous
0

\huge\bf{Answer:-}

Refer the attachment.

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