Question

sin(b+a)+cos(b-a)/sin(b-a)+cos(b+a) =?

Answer 1

$\frac{sin(b+a)+cos(b-a)}{sin(b-a)+cos(b+a)}\\\\=\frac{sin(b+a)+sin(90-b+a)}{sin(b-a)+sin(90-b-a)}\\\\=\frac{2sin(45+a).cos(b-45)}{2sin(45-a).cos(b-45)}\\\\=\frac{sin(45+a)}{sin(45-a)}\\\\or,\\=\frac{cosa+sina}{cosa-sina}$

Answer 2

Step-by-step explanation:

Please refer to the attachment for answer;