Math, asked by PrincePatelK12, 10 months ago

sin(B+C) = √3/2
sin(A + C) = sin B and
sin A = 1/2
and
Find sin(A + B - C)​

Answers

Answered by Martin84
1

Answer:

-1/2

Step-by-step explanation:

 \sin( \alpha  +  \beta )  =  \frac{ \sqrt{3} }{2}  \\  \alpha  +  \beta  =  { \sin - 1} \sin( \frac{\pi}{3} )  \\  \alpha  +  \beta  =  \frac{\pi}{3}  \\  \sin( \alpha )  =  \frac{1}{2}  \\  \alpha  =  \frac{\pi}{6}  \\  \beta  +  \frac{\pi}{3}  =  \frac{\pi}{6}  \\  \beta  =  -  \frac{\pi}{3}  \\  \sin( \alpha  + c)  =  \sin( \beta )  \\  \alpha  + c =  \beta  \\ c =  -  \frac{\pi}{3}   - \frac{\pi}{6}  \\  c =  -  \frac{\pi}{2}  \\  \sin( \alpha  +  \beta  + c)  =    \sin( \frac{\pi}{6} - \frac{\pi}{3}    -  \frac{\pi}{2} )  \\  \sin( \frac{\pi}{6} -  \frac{\pi}{3}  )  \\  -  \sin( \frac{\pi}{3} )  \\  -  \frac{1}{2}

Similar questions