Question

(sinθ - cosθ +1)/(sinθ + cosθ -1) = ?

Answer 1

Answer:

0

Step-by-step explanation:

(Sinx - Cosx +1)(Sinx + Cosx -1)

(Sinx - Cosx +1)( 1 - 1)

= 0

Answer 2

Answer:

$\frac{ \sin(a) - \cos(a) + 1 }{ \sin(a) + \cos(a) - 1 } \\ = \frac{2 \sin( \frac{a}{2} ) \cos( \frac{a}{2} ) - (1 - 2 \sin {}^{2} ( \frac{a}{2} )) + 1 }{2 \sin( \frac{a}{2} ) \cos( \frac{a}{2} ) + 1 - 2 \sin {}^{2} ( \frac{a}{2} ) - 1 } \\ = \frac{2 \sin( \frac{a}{2} ) \cos( \frac{a}{2} ) + 2 \sin {}^{2} ( \frac{a}{2} ) }{2 \sin( \frac{a}{2} ) \cos( \frac{a}{2} ) - 2 \sin {}^{2} ( \frac{a}{2} ) } \\ = \frac{ \cos( \frac{a}{2} ) + \sin( \frac{a}{2} ) }{ \cos( \frac{a}{2} ) - \sin( \frac{a}{2} ) }$

Hope it's helpful