Question

Sin¢+ Cos¢ =√2 calculate tan ¢+ cot$ .
.
. Properly solve pls

Answer 1

hello users .....
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We know that:
sin²x + cos²x = 1

Solution:-
Given that:
sin ¢ + cos ¢ = √2 

Squaring on both side 
we get
(sin ¢ + cos ¢)² = (√2)²

=> sin²¢ + cos²¢ + 2 sin ¢ cos ¢ = 2 

=> 1 + 2 sin ¢ cos ¢ = 2 

=> 2 sin ¢cos ¢= 2 - 1 = 1 

=> sin ¢cos ¢= 1 / 2 

Now,
tan ¢ + cot ¢ = sin ¢ / cos ¢  + cos ¢ / sin ¢ 

=> tan ¢ + cot ¢ = (sin²¢ + cos²¢) / sin ¢ cos ¢ 
(Taking LCM)

=> tan ¢+ cot ¢ = 1 / sin ¢ cos ¢ 

=> tan ¢ + cot ¢ = 1 / (1/2)

=> tan ¢ + cot ¢ = 2 Answer   
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Hope it helps :)

Answer 2

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