Question

sin cube theta plus cos cube theta by sin theta + cos theta=. (with clear explanation) ( very fast)​

Answer 1

Answer:

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Step-by-step explanation:

so here given trigonometric equation is

sin cube theta plus cos cube theta by sin theta +cos theta

so here sin cube+cos cube is in a cube+b cube

so we know that

a cube+b cube=(a+b)(a square+b square-ab)

thus accordingly we get

(sin+cos)(sin square+cos square-sin.cos)/(sin-cos)

=(1-sin.cos)

since sin square+cos square=1

this finally we get

1-sin theta.cos theta