Question

sin inverse of cos teta

Answer 1

let y =sin^-1 cos x

y=π/2 - cos^-1 cos x

.,,,,,,,,,,,,,,,,,,,,

As , y=π/2 - cos^-1cosx is periodic with period 2π.

to draw this graph , we should draw the graph for one interval of length 2π and repeat for entire values of x of length2π.

As we know;

cos^-1(cosx) = $\left \{ {{x; 0\leq x \leq \pi  } \atop {2\pi -x;0\leq2 \pi-x\leq  \pi  }} \right.$

so values of y = π/2 - cos^-1 cos x  by above graph.