Question

Sin inverse x - cox inverse x = pi/ 6

Answer 1

Hey dear

Here is the answer
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${sin}^{ - 1} x - {cos}^{ - 1} x = \frac{\pi}{6} \\ \\ {sin}^{ - 1} x + {cos}^{ - 1} x - 2 {cos}^{ - 1} x = \frac{\pi}{6} \\ \\ \frac{\pi}{2} - 2 {cos}^{ - 1} x = \frac{\pi}{6} \\ \\ 2 {cos}^{ - 1} x = \frac{\pi}{2} - \frac{\pi}{6} \\ \\ 2 {cos}^{ - 1} x = \frac{3\pi - \pi}{6} \\ \\ 2 {cos}^{ - 1} x = \frac{2\pi}{6} = \frac{\pi}{3} \\ \\ {cos}^{ - 1} x = \frac{\pi}{3 \times 2} = \frac{\pi}{6} \\ \\ so...... \\ \\ x = cos \frac{\pi}{6} \\ \\ x = \frac{ \sqrt{3} }{2} \\ \\ \: hope \: it \: helps \: you$