Math, asked by joelraj5790, 11 months ago

sin (log x) द्वितीय कोटि के अवकलज ज्ञात कीजिए

Answers

Answered by amitnrw
0

d²y/dx²   = -(Cos(logx)+ Sin(logx))/x²  यदि y = sin (log x)

Step-by-step explanation:

द्वितीय कोटि के अवकलज ज्ञात कीजिए

y = Sin(log x)

=>  (dy/dx) = Cos(logx)(1/x)  

=>  (dy/dx) = Cos(logx)/x

d²y/dx²   =    Cos(logx)(-1/x²)   + (1/x)(-Sin(logx)(1/x)

=> d²y/dx²   =    -Cos(logx)/x²   - Sin(logx)/x²

=> d²y/dx²   =    (-Cos(logx) - Sin(logx))/x²

=> d²y/dx²   = -(Cos(logx)+ Sin(logx))/x²

और अधिक जानें :

X^{20}  द्वितीय कोटि के अवकलज ज्ञात कीजिए

https://brainly.in/question/15287535

x cos x  द्वितीय कोटि के अवकलज ज्ञात कीजिए

https://brainly.in/question/15287541

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