Question

sin ø/1-cotø+ cosø/1-tanø =sinø+cosø​

Answer 1

Answer:

Step-by-step explanation:

$\frac{sin\beta }{1-cot\beta }$ + $\frac{cos\beta }{1-tan\beta }$ = sinβ + cosβ

L.H. = $\frac{sin^2 \beta }{sin\beta -cos\beta }$ + $\frac{cos^2 \beta }{cos\beta -sin\beta }$ = $\frac{sin^2 \beta -cos^2 \beta }{sin\beta -cos\beta }$ = $\frac{(sin\beta -cos\beta)(sin\beta +cos\beta) }{sin\beta -cos\beta }$ = sinβ + cosβ = R.H.