sin power 6 +cos power 6 +3 sin square cos square =1
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SubjectMatterExpert
Member since Sep 21 2013
Consider, sin6+cos6ө =1-3sin2өcos2ө
(sin2ө)3+(cos2ө)3= (sin2ө+cos2ө)3− 3 (sin2ө cos2ө)(sin2ө+cos2ө) = 1 − 3sin2өcos2ө [Since sin2ө+cos2ө = 1]
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more_horiz
, Student
Member since Dec 10 2008
Consider, sin6ө + cos6ө =1-3sin2өcos2ө
(sin2ө)3 + (cos2ө)3 = (sin2ө + cos2ө)3 − 3 (sin2ө cos2ө)(sin2ө + cos2ө) [since a + b = (a+b)3 − 3ab(a+b)]
= 1 − 3sin2өcos2ө [Since sin2ө + cos2ө = 1]
This is your answer of sin power 6 +cos power 6 +3 sin square cos square =1
Member since Sep 21 2013
Consider, sin6+cos6ө =1-3sin2өcos2ө
(sin2ө)3+(cos2ө)3= (sin2ө+cos2ө)3− 3 (sin2ө cos2ө)(sin2ө+cos2ө) = 1 − 3sin2өcos2ө [Since sin2ө+cos2ө = 1]
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more_horiz
, Student
Member since Dec 10 2008
Consider, sin6ө + cos6ө =1-3sin2өcos2ө
(sin2ө)3 + (cos2ө)3 = (sin2ө + cos2ө)3 − 3 (sin2ө cos2ө)(sin2ө + cos2ө) [since a + b = (a+b)3 − 3ab(a+b)]
= 1 − 3sin2өcos2ө [Since sin2ө + cos2ө = 1]
This is your answer of sin power 6 +cos power 6 +3 sin square cos square =1
112344:
it is very difficult to understand plz do it in notebook then send me pic plz plz its very urgent
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This is the proof, I guess.
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there is a little mistake in 2nd step... according to mine. plz solve my other problems
What mistake exactly? Tell me, and I'll try to get myself right.
no no it is right.. i know what you doing
thnx
You're welcome
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