Math, asked by Lovepreetbrar1, 1 year ago

sin/sec+tan-1+cos/cosec+cot-1=1

Answers

Answered by soumyadarship
87

Step-by-step explanation:

i) sin(a)/{sec(a) + tan(a) - 1} = {sin(a)*cos(a)}/{1 + sin(a) - cos(a)} [Multiplying by cos(a)]


ii) cos(a)/{csc(a) + cot(a) - 1} = {cos(a)*sin(a)}/{1 + cos(a) - sin(a)} [Multiplying by sin(a)]


iii) Thus left side = {sin(a)*cos(a)}/{1 + sin(a) - cos(a)} + {cos(a)*sin(a)}/{1 + cos(a) - sin(a)}


= {cos(a)*sin(a)}[1/{1 + sin(a) - cos(a)} + 1/{1 + cos(a) - sin(a)}]


= {cos(a)*sin(a)}*[{1 + cos(a) - sin(a) + 1 + sin(a) - cos(a)}/{1 + sin(a) - cos(a)*{1 + cos(a) - sin(a)}]


= {cos(a)*sin(a)}*[2/{1 - (sin a - cos a)²} = {cos(a)*sin(a)}*[2/2*sin(a)*cos(a)} = 2sin(a)cos(a)/2sin(a)cos(a) = 1

Answered by Adhityan
227

Answer:


Step-by-step explanation:


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