write a quadratic polynomial , the sum and product of whose zeroes are 3 and -2
Answers
Answered by
5
Let the two zeroes be a (alpha) and b (beta)
According to question,
a+b = 3
ab = -2
FORMULA
p(x) = k{x^2 - (a+b)x + ab} here k is constant
= k{x^2 -3x -2}
taking k =1
the polynomial is
x^2 - 3x -2
hope you like it
According to question,
a+b = 3
ab = -2
FORMULA
p(x) = k{x^2 - (a+b)x + ab} here k is constant
= k{x^2 -3x -2}
taking k =1
the polynomial is
x^2 - 3x -2
hope you like it
Answered by
1
You should know the concept!
If the roots of a quadratic is a and b, then the factor of the quadratic are (x-a) and (x-b). So, tge quadratic formed will be
p(x) = (x-a)(x-b)
p(x)= x² - (a+b)+ ab
Now, since we know that a+b =3 and ab = -2, we can simply put them in the expression and find the quadratic.
p(x)= x²-3x-2
I hope you understand the concept.
All the best!
If the roots of a quadratic is a and b, then the factor of the quadratic are (x-a) and (x-b). So, tge quadratic formed will be
p(x) = (x-a)(x-b)
p(x)= x² - (a+b)+ ab
Now, since we know that a+b =3 and ab = -2, we can simply put them in the expression and find the quadratic.
p(x)= x²-3x-2
I hope you understand the concept.
All the best!
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