Math, asked by panwai21, 1 year ago

sinθ/sin(90°-θ)+cosθ/cos(90°-θ)

Answers

Answered by balakrishna40
1

 \frac{ \sin( \alpha ) }{ \cos( \alpha ) }  +  \frac{ \cos( \alpha ) }{ \sin( \alpha ) }

 \frac{ { \sin }^{2} \alpha  +  { \cos \alpha }^{2}  }{ \sin\alpha  \cos \alpha  }

 =  \csc( \alpha )  \sec( \alpha )

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