sin Sq A.tanA+cossqA.cotA+2sinA.cosA=TanA+cotA=SecA.cosecA. solve this question plzz
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Sin² A tan A + Cos²A Cot A + 2 Sin A Cos A
= Tan A + Cot A = Sec A Cosec A
Sin³ A / Cos A + Cos³ A / Sin A + 2 Sin A Cos A
= [ Sin⁴ A + Cos⁴ A + 2 Sin² A Cos² A ] / [Cos A Sin A]
= ( sin² A + Cos² A)² / (Cos A Sin A)
= Sec A Cosec A
=================
Tan A + Cos A
= sin A/ cos A + Cos A / Sin A
= (sin² A + Cos²A)/ (sin A Cos A)
= Sec A Cosec A
Sin² A tan A + Cos²A Cot A + 2 Sin A Cos A
= Tan A + Cot A = Sec A Cosec A
Sin³ A / Cos A + Cos³ A / Sin A + 2 Sin A Cos A
= [ Sin⁴ A + Cos⁴ A + 2 Sin² A Cos² A ] / [Cos A Sin A]
= ( sin² A + Cos² A)² / (Cos A Sin A)
= Sec A Cosec A
=================
Tan A + Cos A
= sin A/ cos A + Cos A / Sin A
= (sin² A + Cos²A)/ (sin A Cos A)
= Sec A Cosec A
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