Question

sin square 30 degree cos square 45 degree + 4 tan square 30 degree + half sin square 90 degree-2 cos square 90 degree + 1 divided by 24 cos square 0 degree

Answer 1

here is your answer....

Answer 2

Answer:

$Value \: of \\sin^{2}30\degree cos^{2} 45\degree +4 tan^{2} 30\degree \\+\frac{1}{2} sin^{2} 90\degree -2 cos^{2} 90\degree\\ +\frac{1}{24 cos^{2} 0\degree}=0$

Step-by-step explanation:

$Value \: of \\sin^{2}30\degree cos^{2} 45\degree +4 tan^{2} 30\degree \\+\frac{1}{2} sin^{2} 90\degree -2 cos^{2} 90\degree\\ +\frac{1}{24 cos^{2} 0\degree}$

$=\big(\frac{1}{2}\big)^{2} \times \big(\frac{1}{\sqrt{2}}\big)^{2}+4 \big(\frac{1}{\sqrt{3}}\big)^{2}\\+\frac{1}{2}\times 1-2 \times 0\\+\frac{1}{24\times 1^{2}}$

$=\frac{1}{4}\times \frac{1}{2}+4\times \frac{1}{3}+\frac{1}{2}-0+\frac{1}{24}$

$= \frac{1}{8}+\frac{4}{3}+\frac{1}{2}+\frac{1}{24}$

$=\frac{3+32+12+1}{24}$

$=\frac{48}{24}$

$=2$

Therefore,

$Value \: of \\sin^{2}30\degree cos^{2} 45\degree +4 tan^{2} 30\degree \\+\frac{1}{2} sin^{2} 90\degree -2 cos^{2} 90\degree\\ +\frac{1}{24 cos^{2} 0\degree}=2$

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