CBSE BOARD X, asked by mukulgupta4317, 1 year ago

Sin square 30 degree sin square 45 degree sin square 60 degree sin square 90 degree

Answers

Answered by Robin0071
21
Solution:'

given by:-

 { \sin}^{2} 30. { \sin }^{2} 45. { \sin }^{2} 60. { \sin }^{2} 90 \\  {( \frac{1}{2}) }^{2}  \times  {( \frac{1}{ \sqrt{2} } )}^{2}  \times  {( \frac{ \sqrt{3} }{2}) }^{2}  \times  {1}^{2}  \\  \frac{1}{4}   \times  \frac{1}{2}  \times  \frac{3}{4}  \times 1 \\  \frac{3}{32}  \: ans
Answered by saranya428
5

Answer:

Hello.....

sin²30° ×sin²45°×sin²60°×sin²90°

we know that,

sin 30°=1/2

sin 45° =1/2

sin 60° = 3/2

sin 90° = 1

so, = (1/2)²×(1/2)² ×(3/2)² ×(1)²

= 1²/2² ×1 ²/ (2)² × (3)²/2² ×1²

= 1/4×1/2×3/4×1

= 3/32 ....

Hope it helps......

plz mark as brain liest answer.......

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