Sin square theta cos square theta (1 +tan Sq theta) (1+cot Sq theta)
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Answer:
(sin² theta)(cos²theta) (1+ tan²theta) (1+cot²theta)
as we know,
1+tan²theta = sec²theta
and 1+ cot² theta = cosec²theta
then,
(sin²theta)(cos²theta)(sec² theta)(cosec²theta)
and sec²theta = 1/cos²theta
cosec²theta = 1/sin²theta
then, sin²theta cos²theta/sin²theta cos²theta =1
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