Question

Sin square theta +cos square theta

Answer 1

Answer:

1

Step-by-step explanation:

Put sin \theta = \frac{P}{H}, cos \theta = \frac{B}{H},

Sin^2 \theta + Cos^2 \theta= 1

(\frac{P}{H})^2 + (\frac{B}{H})^2 = 1

\frac{(P^2 + B^2)}{H^2} = 1

Ina triangle, by pythogoras,

P^2 + B^2 = H^2

Hence, \frac{H^2}{H^2} = 1.