Math, asked by sy0350825, 6 months ago

दी पेरिमीटर ऑफ़ रेक्टेंगल इस 72 सेंटीमीटर इन लेंथ इस 3 टाइम्स विद फाइंड द एरिया ऑफ रेक्टेंगल ​

Answers

Answered by Anonymous
4

Answer:

Given :-

  • Perimeter of rectangle = 72 cm
  • Length is 3 times of its breadth

To Find :-

Area of rectangle

Solution :-

Let the breadth be x

As we know that

 \huge \mathfrak{Perimeter = 2(l + b)}

 \tt \mapsto72 = 2(3x + x)

 \tt \mapsto \: 72 = 6x + 2x

 \tt \mapsto \: 72 = 8x

 \tt \mapsto \: x =  \dfrac{72}{8}

 \tt \mapsto \: x = 8

Now,

Let's find Length

 \tt \implies \: length \:  = 3x = 3(8) = 24

Now,

Let's find Area of rectangle

As we know that

 \huge \mathfrak{Area = l  \times  b}

 \tt \mapsto \: Area \:  = 24 \times 8

 \tt \mapsto \: Area = 192 cm

Answered by Anonymous
4

Given :-

  • Perimeter of rectangle = 72cm

  • Length = 3 times breadth.

To Find :-

  • Area of rectangle.

Solution :-

Let,

  • Breadth = x

  • Lenght = 3x

Formula used :

\sf{Perimeter = 2(l + b)}

Values :

\dashrightarrow\sf{72 = 2(3x + x)} \\  \\

\dashrightarrow\sf{72 = 6x + 2x} \\  \\

\dashrightarrow\sf{72 = 8x} \\  \\

\dashrightarrow\sf{x =  \frac{72}{8} } \\  \\

\dashrightarrow\underline{\boxed{\textsf{\textbf\red{x = 9}}}} \\  \\

Therefore, x = 9

  • Breadth = x = 9.

  • Length = 3x = 9 × 3 = 27.

Now, We have to find Area of rectangle.

Formula used :

\dashrightarrow\sf{L \times B}

Values :

\dashrightarrow\sf{27 \times 9}\\ \\

\dashrightarrow\underline{\boxed{\textsf{\textbf{\red{243}}}}}

Therefore, Area of rectangle = 243

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