Sin square theta tan theta + cos square theta cot theta + 2 sin theta cos theta equals to tan theta + cot theta
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Answered by
6
Answer:
Step-by-step explanation:
L.H.S:
sin²θtanθ+cos²θcotθ+ 2sinθcosθ
= sin³θ/cosθ + cos³θ/sinθ + 2sinθcosθ
= sin⁴θ + cos⁴θ+ 2sin²θcos²θ/sinθcosθ
= (sin²θ + cos²θ)²/sinθcosθ
= 1/sinθcosθ.
= (sin²θ + cos²θ) / sinθcosθ
= sin²θ/sinθcosθ + cos²θ/sinθcosθ
= sinθ/cosθ + cosθ/sinθ
= tanθ + cotθ
= R.H.S
Answered by
1
Answer:
plz ignore the mistakes.....
Step-by-step explanation:
Plz mark it as branliest
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