Question

sin tetha/1+cos tetha is equal to
(A) cos tetha/1-sin tetha
(B) 1 - cos theta/sin theta (C) 1 - sin theta/cos tetha (D) 1 - cos theta/1-cos tetha​

Answer 1

Answer:

$\huge\mathcal{\green{Bonjour!}}$

$\huge\mathfrak{\red{Answer}}$

$\huge\fbox{\purple{B) \ 1 \ - \ cos \ x/ sin x }}$

Step-by-step explanation:

☆ Question:-

• sin x/1+cos x is equal to?

☆ To find:-

• value of sin x/1+cos x

☆ Required Solution:-

By rationalising the denominator we have;

$\huge \frac{sin \: x}{1 + cos \: x} \times \frac{1 - cos \: x}{1 - cos \: x}$

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$\huge = > \frac{sin \: x(1 - cos \: x)}{1 - {cos}^{2} x}$

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$\huge = > \frac{sin(1 - cos \: x)}{ {sin}^{2}x } = \frac{1 - cos \: x}{sin \: x}$

$\huge\mathcal{\green{All \ the \ very \ best!}}$

$\huge\mathfrak{\red{@MissTranquil}}$

$\huge\fbox{\orange{be \ brainly}}$

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☆ Note:-

: ➝ Here, theta is taken as 'x'.