Question

sin theta by 1 minus cos theta is equal to cos theta + cot theta

Answer 1

Answer:

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Step-by-step explanation:

NOW

$sin^{2}{\theta}+cos^{2}{\theta}=1\\\\\frac{sin{\theta}}{1-cos{\theta}} =\frac{sin{\theta}}{1-cos{\theta}}*\frac{1+cos{\theta}}{1+cos{\theta}} \\=\frac{sin{\theta}(1+cos{\theta})}{1-cos^{2}{\theta}}\\=\frac{sin{\theta}(1+cos{\theta})}{sin^{2}{\theta}}\\\\={(1+cos{\theta})}\frac{1}{sin{\theta}}\\=cosec{\theta}+cot{\theta}$

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