Question

sin theta + cos theta equals to K then 2(sincubeteta+coscubeteta)

Answer 1

Sin(tita)+cos(tita)]^2=sin^2( tita)+cos^2(tita)+2.sin(tita) .cos (tita) =1+2.kSo, sin (tita)+cos(tita) = √1+2kSince we know thatSin^2(tita)+cos^2(tita ...

Answer 2

2 (sincubetheta +coscubetheta)
=2 {(sin^2 theta+cos^2 theta)(sin theta +cos theta)}
=2×1×k
=2k