Question

( sin theta + cos theta)( sec theta + cosec theta) = 2 + sec theta. cosec theta​

Answer 1

Step-by-step explanation:

(sin+cos)(sec+cosec)

=(sin+cos)(1/cos+1/sin)

=(sin+cos)(sin+cos/sincos)

=(sin+cos)²/sincos

=1+2sincos/sincos

=seccosec+2