Math, asked by kagitha363, 5 months ago

sin theta + cos theta whole square + cos theta + sec theta whole square​

Answers

Answered by Anonymous
1

Answer:

[sin theeta + cosec theeta]^2 + [ cos theeta + sec theeta]^2

sin^2 theeta + cosec^2 theeta + 2 sin theeta.cosec theeta + cos^2 theeta + sec^2 theeta + 2 cos theeta sec theeta

here , sin^2 theeta + cos^theeta + 1 , sintheeta . cosec theeta = 1 , costheeta . sec theeta = 1

so , 1+2+2+cosec^2 theeta + sec^2 theeta

here , cosec^2 theeta = 1-cot^2 theeta , sec^2 theeta = 1-tan^2 theeta

then 5+1-cot^2 theeta + 1- tan^2 theeta

7-[cot^2theeta + tan^2 theeta]

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